Tolooooooooongin guys
FunGSi EksPonen
Nilai Fungsi f(x) = aΛ£
Penjelasan dengan langkah-langkah:
6. f(x) = 6Λ£⁺¹, untuk x =(-4, -3, -2 , -1, 0, 1 , 2}
hasil untuk
f(-4) = 6⁻⁴⁺¹ = 6⁻³ = [tex]\sf \frac{1}{216}[/tex]
f(-3) = 6⁻³⁺¹ = 6⁻² = [tex]\sf \frac{1}{36}[/tex]
f(-2) = 6⁻²⁺¹ = 6⁻¹ = [tex]\frac{1}{6}[/tex]
f(-1) = 6⁻¹⁺¹ = 6⁰ = 1
f(0) = 6⁰⁺¹ = 6¹ = 6
f(1) = 6¹⁺¹ = 6² = 36
f(2) = 6²⁺¹ = 6³ = 216
7. f(x) = 2Λ£ + 3Λ£⁻¹ , untuk x = (1,2,3,4,5}
hasil untuk :
f(1) =2¹ + 3¹⁻¹= 2 + 3⁰= 2 + 1= 3
f(2) =2² + 3²⁻¹ = 2² + 3¹ = 4+3= 7
f(3) = 2³ + 3³⁻¹= 2³+ 3²= 8+9 = 17
f(4) = 2⁴ + 3⁴⁻¹ = 2⁴ + 3³ = 16 + 27= 43
f(5) = 2⁵ + 3⁵⁻¹ = 2⁵+ 3⁴ = 32 + 81 = 113
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